p^2+4p=31

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Solution for p^2+4p=31 equation:


Simplifying
p2 + 4p = 31

Reorder the terms:
4p + p2 = 31

Solving
4p + p2 = 31

Solving for variable 'p'.

Reorder the terms:
-31 + 4p + p2 = 31 + -31

Combine like terms: 31 + -31 = 0
-31 + 4p + p2 = 0

Begin completing the square.

Move the constant term to the right:

Add '31' to each side of the equation.
-31 + 4p + 31 + p2 = 0 + 31

Reorder the terms:
-31 + 31 + 4p + p2 = 0 + 31

Combine like terms: -31 + 31 = 0
0 + 4p + p2 = 0 + 31
4p + p2 = 0 + 31

Combine like terms: 0 + 31 = 31
4p + p2 = 31

The p term is 4p.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4p + 4 + p2 = 31 + 4

Reorder the terms:
4 + 4p + p2 = 31 + 4

Combine like terms: 31 + 4 = 35
4 + 4p + p2 = 35

Factor a perfect square on the left side:
(p + 2)(p + 2) = 35

Calculate the square root of the right side: 5.916079783

Break this problem into two subproblems by setting 
(p + 2) equal to 5.916079783 and -5.916079783.

Subproblem 1

p + 2 = 5.916079783 Simplifying p + 2 = 5.916079783 Reorder the terms: 2 + p = 5.916079783 Solving 2 + p = 5.916079783 Solving for variable 'p'. Move all terms containing p to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + p = 5.916079783 + -2 Combine like terms: 2 + -2 = 0 0 + p = 5.916079783 + -2 p = 5.916079783 + -2 Combine like terms: 5.916079783 + -2 = 3.916079783 p = 3.916079783 Simplifying p = 3.916079783

Subproblem 2

p + 2 = -5.916079783 Simplifying p + 2 = -5.916079783 Reorder the terms: 2 + p = -5.916079783 Solving 2 + p = -5.916079783 Solving for variable 'p'. Move all terms containing p to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + p = -5.916079783 + -2 Combine like terms: 2 + -2 = 0 0 + p = -5.916079783 + -2 p = -5.916079783 + -2 Combine like terms: -5.916079783 + -2 = -7.916079783 p = -7.916079783 Simplifying p = -7.916079783

Solution

The solution to the problem is based on the solutions from the subproblems. p = {3.916079783, -7.916079783}

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